Solve A+B+B+B+80+90=100 with No negative numbers

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How to Solve the Math Equation: A+B+B+B+80+90=100 Logically

Question: How can we solve that A+B+B+B+80+90=100 with logical reasoning? A and B must not be negative!

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Correct Answer : 

Silly and crazy ans:

” akkad bakad bambe bo, assi nabbe poore sau “, hence A->akkad & B->bakkad

Mathematical logical Solution:

log [1/(10^10)] = -10 log(10) = -10 ->A

log [1/(10^20)] = -20 log(10) = -20 ->B

Now,

So, LHS: A + 3B + 80 + 90

=> -10 + 3(-20) + 80 + 90

=> 100 -> RHS

Hence proved! ( No negative numbers though

Hence, A is log[1/(10^10)] and B is log[1/(10^20)]

 

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