Question: How can we solve that A+B+B+B+80+90=100 with logical reasoning? A and B must not be negative!
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Correct Answer :
Silly and crazy ans:
” akkad bakad bambe bo, assi nabbe poore sau “, hence A->akkad & B->bakkad
Mathematical logical Solution:
log [1/(10^10)] = -10 log(10) = -10 ->A
log [1/(10^20)] = -20 log(10) = -20 ->B
Now,
So, LHS: A + 3B + 80 + 90
=> -10 + 3(-20) + 80 + 90
=> 100 -> RHS
Hence proved! ( No negative numbers though
Hence, A is log[1/(10^10)] and B is log[1/(10^20)]
Also read: Five Sisters in a Room Puzzle Riddle
