100 coins are lying flat on a table. 10 of them are heads up and 90 are tails up.You can’t see which one is which. How can we split the coins into two piles such that there are same number of heads up in each pile?

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If you toss a coin 10 times and it lands heads up every time, what are the chances it will land heads up if you toss it again?

If A+A=2 , A+B+C=6, then A+B+C*4=? Mathematical puzzle answer

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100 coins are lying flat on a table. 10 of them are heads up and 90 are tails up.You can’t see which one is which. How can we split the coins into two piles such that there are same number of heads up in each pile?

Answer: Make 2 piles with 10 coins and 90 coins each. Now, flip all the coins in the smaller pile.

Solution:

Let’s consider a case
Pile 1: 88T, 2H
Pile 2: 2T, 8H

Flipping the coins in Pile 2

Pile 1: 88T, 2H
Pile 2: 2H, 8T

Pile 1(heads) = Pile 2(heads)

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If you toss a coin 10 times and it lands heads up every time, what are the chances it will land heads up if you toss it again?

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