I'm the part of the bird that's not in the sky. I can swim in the ocean and yet remain dry. What am I?

I’m the part of the bird that’s not in the sky. I can swim in the ocean and yet remain dry. What am I?

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A box of hardware contains nuts and bolts. The bolts account for 25 percent of the number of items in the box. What percentage are the bolts of the entire box?

Why did the teacher have to wear sunglasses?

I cause involuntary movements in your vehicle. What am I?

Solve A+B+B+B+80+90=100 with No negative numbers

What has a face, but no head; hands, but no feet; yet travels everywhere and is usually running?

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I’m the part of the bird that’s not in the sky. I can swim in the ocean and yet remain dry. What am I?

Answer: A shadow.

Solution:

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A shadow.

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A box of hardware contains nuts and bolts. The bolts account for 25 percent of the number of items in the box. What percentage are the bolts of the entire box?

Answer: 20 percent. For example, there are 10 bolts. Since the number of bolts is 25 percent of the number of items, there must be 40 nuts. The total number of items = 10 bolts + 40 nuts = 50. So, 10/50 = 1/5 = 20%.

Solution:

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20 percent. For example, there are 10 bolts. Since the number of bolts is 25 percent of the number of items, there must be 40 nuts. The total number of items = 10 bolts + 40 nuts = 50. So, 10/50 = 1/5 = 20%.

Show Answer

Why did the teacher have to wear sunglasses?

Answer: Because her students were so bright!

Solution:

I cause involuntary movements in your vehicle. What am I?

Answer: Tow Truck

Solution:

Solve A+B+B+B+80+90=100 with No negative numbers

Answer: A is log[1/(10^10)] and B is log[1/(10^20)]

Solution:

Mathematical logical Solution:

log [1/(10^10)] = -10 log(10) = -10 ->A

log [1/(10^20)] = -20 log(10) = -20 ->B

Now,

So, LHS: A + 3B + 80 + 90

=> -10 + 3(-20) + 80 + 90

=> 100 -> RHS

Hence proved! ( No negative numbers though)

Hence, A is log[1/(10^10)] and B is log[1/(10^20)]

What has a face, but no head; hands, but no feet; yet travels everywhere and is usually running?

Answer: A watch.

Solution:

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A watch.

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I’m the part of the bird that’s not in the sky. I can swim in the ocean and yet remain dry. What am I?

Answer: A shadow.

Solution: Show Answer A shadow.

Show Answer

Share with

You may also like..

A box of hardware contains nuts and bolts. The bolts account for 25 percent of the number of items in the box. What percentage are the bolts of the entire box?

Answer: 20 percent. For example, there are 10 bolts. Since the number of bolts is 25 percent of the number of items, there must be 40 nuts. The total number of items = 10 bolts + 40 nuts = 50. So, 10/50 = 1/5 = 20%.

Solution: Show Answer 20 percent. For example, there are 10 bolts. Since the number of bolts is 25 percent of the number of items, there must be 40 nuts. The total number of items = 10 bolts + 40 nuts = 50. So, 10/50 = 1/5 = 20%.

Show Answer

Why did the teacher have to wear sunglasses?

Answer: Because her students were so bright!

Solution:

I cause involuntary movements in your vehicle. What am I?

Answer: Tow Truck

Solution:

Solve A+B+B+B+80+90=100 with No negative numbers

Answer: A is log[1/(10^10)] and B is log[1/(10^20)]

Solution: Mathematical logical Solution: log [1/(10^10)] = -10 log(10) = -10 ->A log [1/(10^20)] = -20 log(10) = -20 ->B Now, So, LHS: A + 3B + 80 + 90 => -10 + 3(-20) + 80 + 90 => 100 -> RHS Hence proved! ( No negative numbers though) Hence, A is log[1/(10^10)] and B is log[1/(10^20)]

What has a face, but no head; hands, but no feet; yet travels everywhere and is usually running?

Answer: A watch.

Solution: Show Answer A watch.

Show Answer

Submit a Comment Cancel reply

Solution:

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A shadow.

Solution:

Show Answer

20 percent. For example, there are 10 bolts. Since the number of bolts is 25 percent of the number of items, there must be 40 nuts. The total number of items = 10 bolts + 40 nuts = 50. So, 10/50 = 1/5 = 20%.

Solution:

Mathematical logical Solution:

log [1/(10^10)] = -10 log(10) = -10 ->A

log [1/(10^20)] = -20 log(10) = -20 ->B

Now,

So, LHS: A + 3B + 80 + 90

=> -10 + 3(-20) + 80 + 90

=> 100 -> RHS

Hence proved! ( No negative numbers though)

Hence, A is log[1/(10^10)] and B is log[1/(10^20)]

Solution:

Show Answer

A watch.