Sherlock Holmes and Doctor Watson were going on a hike through the woods. After a long day of hiking, they stopped for the night. They ate a cold meal, pitched a tent, and went to sleep. Both of them woke up in the middle of the night. “The stars are out tonight,” remarked Doctor Watson. “What does this tell you?” Sherlock asked. “Well,” he replied, “By the positions of the stars, it’s roughly midnight.” “What else does this tell you?” Sherlock asked again. “I don’t know!” Doctor Watson retorted, annoyed. “What does it tell you?” What did the detective notice?
Answer: "Elementary, my dear Watson. Someone has stolen our tent."
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Jack has 8 bricks 7 of them weights the same amount and one is slightly heavier. Using a balance scale, how can Jack find the heavier brick in two weighings?
Answer: First he split them in to piles of 3, 3, and 2 bricks. Then he weighs both groups of 3 with each other. If they balance he knows the brick is one of the 2 unweighed bricks and he can weigh them to find the heaver one. If the the stacks of 3 bricks do not balance, he will weigh 2 of the 3 bricks. If they balance he will know the brick left unweighed is heavier, or if they do not balance, he will find the heavier one.
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First he split them in to piles of 3, 3, and 2 bricks. Then he weighs both groups of 3 with each other. If they balance he knows the brick is one of the 2 unweighed bricks and he can weigh them to find the heaver one. If the the stacks of 3 bricks do not balance, he will weigh 2 of the 3 bricks. If they balance he will know the brick left unweighed is heavier, or if they do not balance, he will find the heavier one.
Show Answer
First he split them in to piles of 3, 3, and 2 bricks. Then he weighs both groups of 3 with each other. If they balance he knows the brick is one of the 2 unweighed bricks and he can weigh them to find the heaver one. If the the stacks of 3 bricks do not balance, he will weigh 2 of the 3 bricks. If they balance he will know the brick left unweighed is heavier, or if they do not balance, he will find the heavier one.