I have 10 books and I label them with their number. I take seven out to read. How many books are left?

Share with

Facebook Comment

A DJ does this to records. I do it to mosquito bites.

What do mathematics teachers like to eat?

What is taken before you can get it?

Solve A+B+B+B+80+90=100 with No negative numbers

I keep things green and keep kids happy during summer time. What am I?

Previous Next

I have 10 books and I label them with their number. I take seven out to read. How many books are left?

Answer: 9! You have token the book with the label seven!

Solution:

Show Answer

9! You have token the book with the label seven!

Show Answer

Share with

You may also like..

A DJ does this to records. I do it to mosquito bites.

Answer: Scratch

Solution:

What do mathematics teachers like to eat?

Answer: Pi.

Solution:

Show Answer

Pi.

Show Answer

What is taken before you can get it?

Answer: Your picture.

Solution:

Solve A+B+B+B+80+90=100 with No negative numbers

Answer: A is log[1/(10^10)] and B is log[1/(10^20)]

Solution:

Mathematical logical Solution:

log [1/(10^10)] = -10 log(10) = -10 ->A

log [1/(10^20)] = -20 log(10) = -20 ->B

Now,

So, LHS: A + 3B + 80 + 90

=> -10 + 3(-20) + 80 + 90

=> 100 -> RHS

Hence proved! ( No negative numbers though)

Hence, A is log[1/(10^10)] and B is log[1/(10^20)]

I keep things green and keep kids happy during summer time. What am I?

Answer: Sprinkler

Solution:

I have 10 books and I label them with their number. I take seven out to read. How many books are left?

Answer: 9! You have token the book with the label seven!

Solution: Show Answer 9! You have token the book with the label seven!

Show Answer

Share with

You may also like..

A DJ does this to records. I do it to mosquito bites.

Answer: Scratch

Solution:

What do mathematics teachers like to eat?

Answer: Pi.

Solution: Show Answer Pi.

Show Answer

What is taken before you can get it?

Answer: Your picture.

Solution:

Solve A+B+B+B+80+90=100 with No negative numbers

Answer: A is log[1/(10^10)] and B is log[1/(10^20)]

Solution: Mathematical logical Solution: log [1/(10^10)] = -10 log(10) = -10 ->A log [1/(10^20)] = -20 log(10) = -20 ->B Now, So, LHS: A + 3B + 80 + 90 => -10 + 3(-20) + 80 + 90 => 100 -> RHS Hence proved! ( No negative numbers though) Hence, A is log[1/(10^10)] and B is log[1/(10^20)]

I keep things green and keep kids happy during summer time. What am I?

Answer: Sprinkler

Solution:

Solution:

Show Answer

9! You have token the book with the label seven!

Solution:

Show Answer

Pi.

Solution:

Mathematical logical Solution:

log [1/(10^10)] = -10 log(10) = -10 ->A

log [1/(10^20)] = -20 log(10) = -20 ->B

Now,

So, LHS: A + 3B + 80 + 90

=> -10 + 3(-20) + 80 + 90

=> 100 -> RHS

Hence proved! ( No negative numbers though)

Hence, A is log[1/(10^10)] and B is log[1/(10^20)]