I have legs but never walk, I may have flowers but no soil, I hold food but never eat.

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My head bobs lazily in the sun. You think I’m cute. For my face is yellow my hair is white and my body is green.

I mirror your actions. What am I?

What does a rain cloud wear under their raincoat?

When this is found in a road you are forced to make a decision.

Solve A+B+B+B+80+90=100 with No negative numbers

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I have legs but never walk, I may have flowers but no soil, I hold food but never eat.

Answer: table

Solution:

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My head bobs lazily in the sun. You think I’m cute. For my face is yellow my hair is white and my body is green.

Answer: daisy

Solution:

I mirror your actions. What am I?

Answer: Copycat

Solution:

What does a rain cloud wear under their raincoat?

Answer: Thunderware

Solution:

When this is found in a road you are forced to make a decision.

Answer: fork

Solution:

Solve A+B+B+B+80+90=100 with No negative numbers

Answer: A is log[1/(10^10)] and B is log[1/(10^20)]

Solution:

Mathematical logical Solution:

log [1/(10^10)] = -10 log(10) = -10 ->A

log [1/(10^20)] = -20 log(10) = -20 ->B

Now,

So, LHS: A + 3B + 80 + 90

=> -10 + 3(-20) + 80 + 90

=> 100 -> RHS

Hence proved! ( No negative numbers though)

Hence, A is log[1/(10^10)] and B is log[1/(10^20)]

I have legs but never walk, I may have flowers but no soil, I hold food but never eat.

Answer: table

Solution:

Share with

You may also like..

My head bobs lazily in the sun. You think I’m cute. For my face is yellow my hair is white and my body is green.

Answer: daisy

Solution:

I mirror your actions. What am I?

Answer: Copycat

Solution:

What does a rain cloud wear under their raincoat?

Answer: Thunderware

Solution:

When this is found in a road you are forced to make a decision.

Answer: fork

Solution:

Solve A+B+B+B+80+90=100 with No negative numbers

Answer: A is log[1/(10^10)] and B is log[1/(10^20)]

Solution: Mathematical logical Solution: log [1/(10^10)] = -10 log(10) = -10 ->A log [1/(10^20)] = -20 log(10) = -20 ->B Now, So, LHS: A + 3B + 80 + 90 => -10 + 3(-20) + 80 + 90 => 100 -> RHS Hence proved! ( No negative numbers though) Hence, A is log[1/(10^10)] and B is log[1/(10^20)]

Solution:

Mathematical logical Solution:

log [1/(10^10)] = -10 log(10) = -10 ->A

log [1/(10^20)] = -20 log(10) = -20 ->B

Now,

So, LHS: A + 3B + 80 + 90

=> -10 + 3(-20) + 80 + 90

=> 100 -> RHS

Hence proved! ( No negative numbers though)

Hence, A is log[1/(10^10)] and B is log[1/(10^20)]