Five baby boomer couples each have one child. Each child is a different age than any of the other children. Each child has a favorite toy which is different from any of the other children’s favorite toys. Each family eats at only one fast food restaurant. No two women have the same name and no two men have the same name. The children’s names are not known. The child who plays with trains is the youngest. Bill’s child plays with a GI Joe. Julie’s child likes Pokeman. Mike’s family eats at Taco Bell. The family of the 4 year old likes Kentucky Fried Chicken. The oldest child is four years older than Marie’s child. The child who plays with Barbie is 8 years old. The child with the age is in the middle, has a mother named Marie. The child in the family that eats at McDonalds has a two year age difference with Larry’s child. Carol is the mother in the family that eats at Dairy Queen. The child that plays Nintendo likes Burger King. Steve’s child is two years apart in age from the child of the family that eats at Kentucky Fried Chicken. The child that plays with trains is two years apart from the 6 year old. The child that eats at McDonalds is two years older or younger than Regina’s child. Lisa’s child is 10. Who is married to George?
Answer: Lisa is married to George, and their 10 year old plays with Nintendo. They like to eat at Burger King. The associations are: Child age 4, mother Regina, Father Larry, trains, KFC Child age 6, mother Julie, Father Steve, Pokeman, McDonalds Child age 8, mother Marie, Father Mike, Barbie, Taco Bell Child age 10, mother Lisa, Father George, Nintendo, Burger King Child age 12, mother Carol, Father Bill, GI Joe, Dairy Queen To solve, draw a grid with five rows and five columns. Across the top, above the columns, write Age, Mother, Father, Toy and Food. Figure out the known ages and write them in order in the first column. One child's age is unknown at first. However, once the youngest child is discovered (the one who plays with trains) it is then known that the oldest child is the child with the unknown age. Through additional clues, it is possible to determine that the oldest child is age 12. Take the clue, Lisa?s child is 10. In the mother column corresponding to the age 10, you would write LISA (Maybe circle it, because it is the correct answer.) In the mother column for every other age, write "not Lisa". Do this for each clue. If you know the answer because of a clue, write it in the appropriate column, and then be sure to write "not such and such" in all the other rows for that clue. For example, "The youngest child plays with trains", would result in "not trains" for any child you can tell isn?t the youngest, but you can?t write "trains" for any child, because you don?t know which child is the youngest at first. Eventually, you may find that "mother not Marie" is on every line except one, and then you would know that Marie is the mother on the empty line.
Solution:
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Lisa is married to George, and their 10 year old plays with Nintendo. They like to eat at Burger King. The associations are: Child age 4, mother Regina, Father Larry, trains, KFC Child age 6, mother Julie, Father Steve, Pokeman, McDonalds Child age 8, mother Marie, Father Mike, Barbie, Taco Bell Child age 10, mother Lisa, Father George, Nintendo, Burger King Child age 12, mother Carol, Father Bill, GI Joe, Dairy Queen To solve, draw a grid with five rows and five columns. Across the top, above the columns, write Age, Mother, Father, Toy and Food. Figure out the known ages and write them in order in the first column. One child’s age is unknown at first. However, once the youngest child is discovered (the one who plays with trains) it is then known that the oldest child is the child with the unknown age. Through additional clues, it is possible to determine that the oldest child is age 12. Take the clue, Lisa?s child is 10. In the mother column corresponding to the age 10, you would write LISA (Maybe circle it, because it is the correct answer.) In the mother column for every other age, write “not Lisa”. Do this for each clue. If you know the answer because of a clue, write it in the appropriate column, and then be sure to write “not such and such” in all the other rows for that clue. For example, “The youngest child plays with trains”, would result in “not trains” for any child you can tell isn?t the youngest, but you can?t write “trains” for any child, because you don?t know which child is the youngest at first. Eventually, you may find that “mother not Marie” is on every line except one, and then you would know that Marie is the mother on the empty line.
Show Answer
Lisa is married to George, and their 10 year old plays with Nintendo. They like to eat at Burger King. The associations are: Child age 4, mother Regina, Father Larry, trains, KFC Child age 6, mother Julie, Father Steve, Pokeman, McDonalds Child age 8, mother Marie, Father Mike, Barbie, Taco Bell Child age 10, mother Lisa, Father George, Nintendo, Burger King Child age 12, mother Carol, Father Bill, GI Joe, Dairy Queen To solve, draw a grid with five rows and five columns. Across the top, above the columns, write Age, Mother, Father, Toy and Food. Figure out the known ages and write them in order in the first column. One child’s age is unknown at first. However, once the youngest child is discovered (the one who plays with trains) it is then known that the oldest child is the child with the unknown age. Through additional clues, it is possible to determine that the oldest child is age 12. Take the clue, Lisa?s child is 10. In the mother column corresponding to the age 10, you would write LISA (Maybe circle it, because it is the correct answer.) In the mother column for every other age, write “not Lisa”. Do this for each clue. If you know the answer because of a clue, write it in the appropriate column, and then be sure to write “not such and such” in all the other rows for that clue. For example, “The youngest child plays with trains”, would result in “not trains” for any child you can tell isn?t the youngest, but you can?t write “trains” for any child, because you don?t know which child is the youngest at first. Eventually, you may find that “mother not Marie” is on every line except one, and then you would know that Marie is the mother on the empty line.
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Answer: A shoe.
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There are 100 light bulbs lined up in a row in a long room. Each bulb has its own switch and is currently switched off. The room has an entry door and an exit door. There are 100 people lined up outside the entry door. Each bulb is numbered consecutively from 1 to 100. So is each person. Person No. 1 enters the room, switches on every bulb, and exits. Person No. 2 enters and flips the switch on every second bulb (turning off bulbs 2, 4, 6, …). Person No. 3 enters and flips the switch on every third bulb (changing the state on bulbs 3, 6, 9, …). This continues until all 100 people have passed through the room. What is the final state of bulb No. 64? And how many of the light bulbs are illuminated after the 100th person has passed through the room?
Answer: First think who will operate each bulb, obviously person #2 will do all the even numbers, and say person #10 will operate all the bulbs that end in a zero. So who would operate for example bulb 48: Persons numbered: 1 & 48, 2 & 24, 3 & 16, 4 & 12, 6 & 8 ........ That is all the factors (numbers by which 48 is divisible) will be in pairs. This means that for every person who switches a bulb on there will be someone to switch it off. This willl result in the bulb being back at it's original state. So why aren't all the bulbs off? Think of bulb 36:- The factors are: 1 & 36, 2 & 13, 6 & 6 Well in this case whilst all the factors are in pairs the number 6 is paired with it's self. Clearly the sixth person will only flick the bulb once and so the pairs don't cancel. This is true of all the square numbers. There are 10 square numbers between 1 and 100 (1, 4, 9, 16, 25, 36, 49, 64, 81 & 100) hence 10 bulbs remain on.
Solution:
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First think who will operate each bulb, obviously person #2 will do all the even numbers, and say person #10 will operate all the bulbs that end in a zero. So who would operate for example bulb 48: Persons numbered: 1 & 48, 2 & 24, 3 & 16, 4 & 12, 6 & 8 …….. That is all the factors (numbers by which 48 is divisible) will be in pairs. This means that for every person who switches a bulb on there will be someone to switch it off. This willl result in the bulb being back at it’s original state. So why aren’t all the bulbs off? Think of bulb 36:- The factors are: 1 & 36, 2 & 13, 6 & 6 Well in this case whilst all the factors are in pairs the number 6 is paired with it’s self. Clearly the sixth person will only flick the bulb once and so the pairs don’t cancel. This is true of all the square numbers. There are 10 square numbers between 1 and 100 (1, 4, 9, 16, 25, 36, 49, 64, 81 & 100) hence 10 bulbs remain on.
Show Answer
First think who will operate each bulb, obviously person #2 will do all the even numbers, and say person #10 will operate all the bulbs that end in a zero. So who would operate for example bulb 48: Persons numbered: 1 & 48, 2 & 24, 3 & 16, 4 & 12, 6 & 8 …….. That is all the factors (numbers by which 48 is divisible) will be in pairs. This means that for every person who switches a bulb on there will be someone to switch it off. This willl result in the bulb being back at it’s original state. So why aren’t all the bulbs off? Think of bulb 36:- The factors are: 1 & 36, 2 & 13, 6 & 6 Well in this case whilst all the factors are in pairs the number 6 is paired with it’s self. Clearly the sixth person will only flick the bulb once and so the pairs don’t cancel. This is true of all the square numbers. There are 10 square numbers between 1 and 100 (1, 4, 9, 16, 25, 36, 49, 64, 81 & 100) hence 10 bulbs remain on.
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