Not a burden for its weight and daily carried out, He who takes it wishes it had never come about
Answer: punishment
Solution:
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A man walks into a bathroom shoots himself in the head. Later he walks out unharmed. How did he survive?
Answer: He shot his reflection in the mirror.
Solution:
A group of campers have been on vacation so long, that they’ve forgotten the day of the week. The following conversation ensues. Darryl: What’s the day? I don’t think it is Thursday, Friday or Saturday. Tracy: Well that doesn’t narrow it down much. Yesterday was Sunday. Melissa: Yesterday wasn’t Sunday, tomorrow is Sunday. Ben: The day after tomorrow is Saturday. Adrienne: The day before yesterday was Thursday. Susie: Tomorrow is Saturday. David: I know that the day after tomorrow is not Friday. If only one person’s statement is true, what day of the week is it?
Answer: It is Wednesday. If it was any other day of the week, more than one statement would be true. To solve the riddle, evaluate each person's statement and write down what day it could be according to the statement. David's statement indicates it could be any day of the week except for Wednesday. When you list the days that it could be according to everyone's statement, it turns out Wednesday is the day mentioned only one time. Darryl: Sunday, Monday, Tuesday, or Wednesday Tracy: Monday Melissa: Saturday Ben: Thursday Adrienne: Saturday Susie: Friday David: Sunday, Monday, Tuesday, Thursday, Friday or Saturday
Solution:
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It is Wednesday. If it was any other day of the week, more than one statement would be true. To solve the riddle, evaluate each person’s statement and write down what day it could be according to the statement. David’s statement indicates it could be any day of the week except for Wednesday. When you list the days that it could be according to everyone’s statement, it turns out Wednesday is the day mentioned only one time. Darryl: Sunday, Monday, Tuesday, or Wednesday Tracy: Monday Melissa: Saturday Ben: Thursday Adrienne: Saturday Susie: Friday David: Sunday, Monday, Tuesday, Thursday, Friday or Saturday
Show Answer
It is Wednesday. If it was any other day of the week, more than one statement would be true. To solve the riddle, evaluate each person’s statement and write down what day it could be according to the statement. David’s statement indicates it could be any day of the week except for Wednesday. When you list the days that it could be according to everyone’s statement, it turns out Wednesday is the day mentioned only one time. Darryl: Sunday, Monday, Tuesday, or Wednesday Tracy: Monday Melissa: Saturday Ben: Thursday Adrienne: Saturday Susie: Friday David: Sunday, Monday, Tuesday, Thursday, Friday or Saturday
Who Is Wearing A Hat ? – tricky Puzzle
Answer: Both Alex and Carl are wearing hats.
Solution:
Answer: Both Alex and Carl are wearing hats.
Reason:
As per given information we understand that, Bob is not wearing a Hat, Carl is wearing a hat.
Now if Alex doesn’t wear a Hat, than Bob must wear a Hat.
But he is not wearing a Hat. So it implies Alex is also wearing a Hat.
So Alex and Carl are wearing hats.
Answer: Both Alex and Carl are wearing hats.
Reason:
As per given information we understand that, Bob is not wearing a Hat, Carl is wearing a hat.
Now if Alex doesn’t wear a Hat, than Bob must wear a Hat.
But he is not wearing a Hat. So it implies Alex is also wearing a Hat.
So Alex and Carl are wearing hats.
You and nine other individuals have been captured by super intelligent alien overlords. The aliens think humans look quite tasty, but their civilization forbids eating highly logical and cooperative beings. Unfortunately, they’re not sure whether you qualify, so they decide to give you all a test. Through its universal translator, the alien guarding you tells you the following: You will be placed in a single-file line facing forward in size order so that each of you can see everyone lined up ahead of you. You will not be able to look behind you or step out of line. Each of you will have either a black or a white hat on your head assigned randomly, and I won’t tell you how many of each color there are. When I say to begin, each of you must guess the color of your hat starting with the person in the back and moving up the line. And don’t even try saying words other than black or white or signaling some other way, like intonation or volume; you’ll all be eaten immediately. If at least nine of you guess correctly, you’ll all be spared. You have five minutes to discuss and come up with a plan, and then I’ll line you up, assign your hats, and we’ll begin. Can you think of a strategy guaranteed to save everyone? Alex Gendler shows how.
Answer: Let's see how it would play out if the hats were distributed like this. The tallest captive sees three black hats in front of him, so he says "black," telling everyone else he sees an odd number of black hats. He gets his own hat color wrong, but that's okay since you're collectively allowed to have one wrong answer. Prisoner two also sees an odd number of black hats, so she knows hers is white, and answers correctly. Prisoner three sees an even number of black hats, so he knows that his must be one of the black hats the first two prisoners saw. Prisoner four hears that and knows that she should be looking for an even number of black hats since one was behind her. But she only sees one, so she deduces that her hat is also black. Prisoners five through nine are each looking for an odd number of black hats, which they see, so they figure out that their hats are white. Now it all comes down to you at the front of the line. If the ninth prisoner saw an odd number of black hats, that can only mean one thing. You'll find that this strategy works for any possible arrangement of the hats. The first prisoner has a 50% chance of giving a wrong answer about his own hat, but the parity information he conveys allows everyone else to guess theirs with absolute certainty. Each begins by expecting to see an odd or even number of hats of the specified color. If what they count doesn't match, that means their own hat is that color. And every time this happens, the next person in line will switch the parity they expect to see. So that's it, you're free to go. It looks like these aliens will have to go hungry, or find some less logical organisms to abduct.
Solution:
Show Answer
Let’s see how it would play out if the hats were distributed like this. The tallest captive sees three black hats in front of him, so he says “black,” telling everyone else he sees an odd number of black hats. He gets his own hat color wrong, but that’s okay since you’re collectively allowed to have one wrong answer. Prisoner two also sees an odd number of black hats, so she knows hers is white, and answers correctly. Prisoner three sees an even number of black hats, so he knows that his must be one of the black hats the first two prisoners saw. Prisoner four hears that and knows that she should be looking for an even number of black hats since one was behind her. But she only sees one, so she deduces that her hat is also black. Prisoners five through nine are each looking for an odd number of black hats, which they see, so they figure out that their hats are white. Now it all comes down to you at the front of the line. If the ninth prisoner saw an odd number of black hats, that can only mean one thing. You’ll find that this strategy works for any possible arrangement of the hats. The first prisoner has a 50% chance of giving a wrong answer about his own hat, but the parity information he conveys allows everyone else to guess theirs with absolute certainty. Each begins by expecting to see an odd or even number of hats of the specified color. If what they count doesn’t match, that means their own hat is that color. And every time this happens, the next person in line will switch the parity they expect to see. So that’s it, you’re free to go. It looks like these aliens will have to go hungry, or find some less logical organisms to abduct.
Show Answer
Let’s see how it would play out if the hats were distributed like this. The tallest captive sees three black hats in front of him, so he says “black,” telling everyone else he sees an odd number of black hats. He gets his own hat color wrong, but that’s okay since you’re collectively allowed to have one wrong answer. Prisoner two also sees an odd number of black hats, so she knows hers is white, and answers correctly. Prisoner three sees an even number of black hats, so he knows that his must be one of the black hats the first two prisoners saw. Prisoner four hears that and knows that she should be looking for an even number of black hats since one was behind her. But she only sees one, so she deduces that her hat is also black. Prisoners five through nine are each looking for an odd number of black hats, which they see, so they figure out that their hats are white. Now it all comes down to you at the front of the line. If the ninth prisoner saw an odd number of black hats, that can only mean one thing. You’ll find that this strategy works for any possible arrangement of the hats. The first prisoner has a 50% chance of giving a wrong answer about his own hat, but the parity information he conveys allows everyone else to guess theirs with absolute certainty. Each begins by expecting to see an odd or even number of hats of the specified color. If what they count doesn’t match, that means their own hat is that color. And every time this happens, the next person in line will switch the parity they expect to see. So that’s it, you’re free to go. It looks like these aliens will have to go hungry, or find some less logical organisms to abduct.
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