You can touch me, You can break me, You should win me if you want to be mine. What am I?
Answer: A heart.
Solution:
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Plant Tortoise Caterpillar Bug Puzzle With Answer | Maths riddle
Answer:
Solution:
Explanation
Equation 1: 5 + 10 + 10 = 25 (So the value of a PLANT with 5 leaves is 5; Also note that there are two plants one beneath the other in second and third part of the equation 1.
Equation 2: 8 + 8 + 8 = 24 (If you look closely, you can see the number 3 on top of each Tortoises. So the value of a TORTOISE = 5)
Equation 3: 2 x 2 x 2 = 8 (So the value of a CATERPILLAR = 2)
Equation 4: 3 + 3 + (-3) = 3 (Since on bug is moving backwards its value is negative. So the value of one BUG = 3)
Equation 5: (5 + 3) + (4 + 2 + 2) x (3 + 3)
(Here in the first part of equation there is a bug on the face of the Tortoise and the Tortoise has no number 3 on its body)
(In the second part of this equation, there are only 4 leaves for the plant and you can see two Caterpillars in the plant pot)
(In the third part of this equation, there are two bugs, one beneath the other)
=> 8 + 8 x 6
=> 8 + 48
=> 56
Final Answer = 56
Explanation
Equation 1: 5 + 10 + 10 = 25 (So the value of a PLANT with 5 leaves is 5; Also note that there are two plants one beneath the other in second and third part of the equation 1.
Equation 2: 8 + 8 + 8 = 24 (If you look closely, you can see the number 3 on top of each Tortoises. So the value of a TORTOISE = 5)
Equation 3: 2 x 2 x 2 = 8 (So the value of a CATERPILLAR = 2)
Equation 4: 3 + 3 + (-3) = 3 (Since on bug is moving backwards its value is negative. So the value of one BUG = 3)
Equation 5: (5 + 3) + (4 + 2 + 2) x (3 + 3)
(Here in the first part of equation there is a bug on the face of the Tortoise and the Tortoise has no number 3 on its body)
(In the second part of this equation, there are only 4 leaves for the plant and you can see two Caterpillars in the plant pot)
(In the third part of this equation, there are two bugs, one beneath the other)
=> 8 + 8 x 6
=> 8 + 48
=> 56
Final Answer = 56
The sum of the present ages of a father and his son is 60 years. Six years ago, father’s age was five times the age of the son. After 6 years, What is son’s age?
Answer: 14 years
Solution:
The sum of the present ages of a father and his son is 60 years. Six years ago, father’s age was five times the age of the son. After 6 years, son’s age will be:
Answer : 14 years
Explanation:
Let the present ages of son and father be x and (60 –x) years respectively.
Then, (60 – x) – 6 = 5(x – 6)
54 – x = 5x – 30
6x = 84
x = 14.
Son’s age after 6 years = (x+ 6) = 20 years..
The sum of the present ages of a father and his son is 60 years. Six years ago, father’s age was five times the age of the son. After 6 years, son’s age will be:
Answer : 14 years
Let the present ages of son and father be x and (60 –x) years respectively.
Then, (60 – x) – 6 = 5(x – 6)
54 – x = 5x – 30
6x = 84
x = 14.
Son’s age after 6 years = (x+ 6) = 20 years..
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