Chinese Couple Equation Puzzle with answer
Answer: 46
Solution:
Explanation :
Equation 1:
10+10+10=30 ( here couple having yellow bag in hands)
Equation 2 :
5+5+5=15
Equation 3:
2 yellow bags+ 1 yellow +1 yellow=24
12+6+6=24
Equation 4:
6+10*4=?
apply BODMAS
6+(40)=46
Correct answer is 46
Hint: one yellow bag (6) + two brown bangs (10)+chines couple without yellow bag in hand(10-6=4)
Explanation :
Equation 1:
10+10+10=30 ( here couple having yellow bag in hands)
Equation 2 :
5+5+5=15
Equation 3:
2 yellow bags+ 1 yellow +1 yellow=24
12+6+6=24
Equation 4:
6+10*4=?
apply BODMAS
6+(40)=46
Correct answer is 46
Hint: one yellow bag (6) + two brown bangs (10)+chines couple without yellow bag in hand(10-6=4)
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Jack has 8 bricks 7 of them weights the same amount and one is slightly heavier. Using a balance scale, how can Jack find the heavier brick in two weighings?
Answer: First he split them in to piles of 3, 3, and 2 bricks. Then he weighs both groups of 3 with each other. If they balance he knows the brick is one of the 2 unweighed bricks and he can weigh them to find the heaver one. If the the stacks of 3 bricks do not balance, he will weigh 2 of the 3 bricks. If they balance he will know the brick left unweighed is heavier, or if they do not balance, he will find the heavier one.
Solution:
Show Answer
First he split them in to piles of 3, 3, and 2 bricks. Then he weighs both groups of 3 with each other. If they balance he knows the brick is one of the 2 unweighed bricks and he can weigh them to find the heaver one. If the the stacks of 3 bricks do not balance, he will weigh 2 of the 3 bricks. If they balance he will know the brick left unweighed is heavier, or if they do not balance, he will find the heavier one.
Show Answer
First he split them in to piles of 3, 3, and 2 bricks. Then he weighs both groups of 3 with each other. If they balance he knows the brick is one of the 2 unweighed bricks and he can weigh them to find the heaver one. If the the stacks of 3 bricks do not balance, he will weigh 2 of the 3 bricks. If they balance he will know the brick left unweighed is heavier, or if they do not balance, he will find the heavier one.
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