Two sentries were on duty outside a barracks. One faced up the road to watch for anyone approaching from the North. The other looked down the road to see if anyone approached from the South. Suddenly one of them said to the other, “Why are you smiling?” How did he know that his companion was smiling?
Answer: Although the guards were looking in opposite directions, they were not back to back. They were facing each other.
Solution:
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Word spelled incorrectly in dictionary Riddle
Answer: “INCORRECTLY”
Solution:
Riddle with an answer: Which word is spelled incorrectly in the dictionary?
In this post, we have revealed the answer for Which word in the dictionary is spelled incorrectly tricky riddle. Share your answer and thoughts in the comments box below
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Correct answer:
“INCORRECTLY”
Knowledge increases by sharing 🙂
Riddle with an answer: Which word is spelled incorrectly in the dictionary?
In this post, we have revealed the answer for Which word in the dictionary is spelled incorrectly tricky riddle. Share your answer and thoughts in the comments box below
Show answer
Correct answer:
“INCORRECTLY”
Knowledge increases by sharing 🙂
100 animals 100 dollars riddle answer
Answer: 5 cows =$50, 1 pig =$3. 94 ducks =$47
Solution:
Answer : 5 cows =$50
1 pig =$3
94 ducks =$47
Explanation:
let number of cows be x
let the number of pigs be y
then the number of chickens = 100-x-y
10x + 3y + .5(100-x-y) < 100
times 2
20x + 6y + 100 – x – y < 200
19x + 5y < 100
consider 19x + 5y = 100
But , what is the question?
Do you want the different combinations you can buy? Do we want as close as possible to $100?
Remember x and y have to be positive integers.
so x has to be between 1 and 5
form a table with columns
x, y, and 100-x-y, and cost
1 16 83 99.50
1 15 82 86.00
…
5 1 94 100
x=5, y=1 is the only combination that will use all the money
He should buy 5 cows, 1 pig and 94 chickens
5+1+94 = 100
$50 + $3 + $47 = $100
Answer : 5 cows =$50
1 pig =$3
94 ducks =$47
Explanation:
let number of cows be x
let the number of pigs be y
then the number of chickens = 100-x-y
10x + 3y + .5(100-x-y) < 100
times 2
20x + 6y + 100 – x – y < 200
19x + 5y < 100
consider 19x + 5y = 100
But , what is the question?
Do you want the different combinations you can buy? Do we want as close as possible to $100?
Remember x and y have to be positive integers.
so x has to be between 1 and 5
form a table with columns
x, y, and 100-x-y, and cost
1 16 83 99.50
1 15 82 86.00
…
5 1 94 100
x=5, y=1 is the only combination that will use all the money
He should buy 5 cows, 1 pig and 94 chickens
5+1+94 = 100
$50 + $3 + $47 = $100
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