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Born in the past, but only lives in the present. Sometimes false, always personal.
Answer: A memory
Solution:
Picture three boxes containing fruit. The first box is marked peaches, the second is marked oranges, and the third box is marked peaches and oranges. Each of the boxes is labeled incorrectly. How could you label each box correctly if you were allowed to select only one fruit from one of the boxes?
Answer: First you select a fruit from the box marked peaches and oranges. If it was a orange you selected, you know that the box could only contain oranges. If it was a peach, you know that the box could only contain peaches since each box is incorrectly marked. If, for example an orange was selected, you would mark that box oranges and switch the other two incorrect labels around. Now all three would be correctly labeled.
Solution:
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First you select a fruit from the box marked peaches and oranges. If it was a orange you selected, you know that the box could only contain oranges. If it was a peach, you know that the box could only contain peaches since each box is incorrectly marked. If, for example an orange was selected, you would mark that box oranges and switch the other two incorrect labels around. Now all three would be correctly labeled.
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How long the scooter Tyre run?
Answer: 7.5 KM
Solution:
First run 2.5 km and change the 1st tyre with stepney. Now kms remains in 1st Tyre: 2.5 km, 2nd tyre: 2.5 km, Stepney : 5 km
Again run for 2.5 km and this time change 2nd tyre with 1st tyre: Now kms remains 1st tyre: 2.5 km, 2nd tyre :0 km ,stepney : 2.5 km.
Now run 2.5 km with remaining 1st tyre and stepney .
Total: 2.5+2.5+2.5=7.5
First run 2.5 km and change the 1st tyre with stepney. Now kms remains in 1st Tyre: 2.5 km, 2nd tyre: 2.5 km, Stepney : 5 km
Again run for 2.5 km and this time change 2nd tyre with 1st tyre: Now kms remains 1st tyre: 2.5 km, 2nd tyre :0 km ,stepney : 2.5 km.
Now run 2.5 km with remaining 1st tyre and stepney .
Total: 2.5+2.5+2.5=7.5