You want to send a valuable object to a friend. You have a box which is more than large enough to contain the object. You have several locks with keys. The box has a locking ring which is more than large enough to have a lock attached. But your friend does not have the key to any lock that you have. How do you do it? Note that you cannot send a key in an unlocked box, since it might be copied.
Answer: Attach a lock to the ring. Send it to her. She attaches her own lock and sends it back. You remove your lock and send it back to her. She removes her lock.
Solution:
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I have memories, but none of my own, whatever’s on my inside is what is shown. If I’m ever different it’s because you changed me, I feel like a decoration, here for you to arrange me. What am I?
Answer: The riddle "Frozen Memories" is unanswered. Do you know the answer? If so, click ANSWER and add your answer in the comments section.
Solution:
if 2+9=711 then find 12+3=??? number Puzzle with answer
Answer: 915
Solution:
if you look at the question we have equations as
2+9=711
14+6=820;
17+11=628
then 12+3=??
from Equation 1
2+9=711
2+9=(2-9)(2+9)
= 711
here we used a formula called a+b=(a-b)(a+b)
similarly for remaining equations
Equation:2
14+6=(14-6)(14+6)=820
Equation:3
17+11=(17-11)(17+11)=628
now we have 12+3=??
12+3=(12-3)(12+3)=915
12+3=915 is the correct answer
if you look at the question we have equations as
2+9=711
14+6=820;
17+11=628
then 12+3=??
from Equation 1
2+9=711
2+9=(2-9)(2+9)
= 711
here we used a formula called a+b=(a-b)(a+b)
similarly for remaining equations
Equation:2
14+6=(14-6)(14+6)=820
Equation:3
17+11=(17-11)(17+11)=628
now we have 12+3=??
12+3=(12-3)(12+3)=915
12+3=915 is the correct answer
A watchmaker was telephoned urgently to make a house call to replace the broken hands on a clock. He was sik so he sent his apprentice. The apprentice was thorough. When he finished inspecting the clock it was dark. Assuming his work was done, he attached the new hands and set the clock by his pocket watch. It was sic o’clock, so he set the big hand at the 12 and the little hand at the 6. The apprectice returned, but soon the telephone rang. He picked up to his angry client: “You didn’t do the job right. The clock shows the wrong time.” Surprised he hurried back. He found the clock showing not much past eight. He handed is watch to the client and showed her that her clock was not even one second late. The client had to agree. Early the nect morning, the client telephoned to say the clock has apparently gone berserk, hands were moving around the clock at will. The apprentice again rushed over, the clock showed a little past seven. After checking his watch he yelled: “You are making fun of me! Your clock shows the right time!” Have you figured out whats going on?
Answer: As the problem says the apprentice mixed up the hands so that the minute hand was short and the hour hand was long. The first time the apprentice returned to the client was about 2 hours and 10 minutes after he had set the clock at six.The long had moved olny from twelve to a little past two. The little made two whole circles and an additional 10 minutes. Thus the clock showed the correct time. The next day around 7:o5 a.m.he came a second time,13 hours and 15 minutes after he had set the clock for six. The long had, acting as the hour hand,covered 13 hours to reach 1. The short hand made 13 full circles and 5 minutes, reaching 7, So the clock showed the correct time again.
Solution:
Show Answer
As the problem says the apprentice mixed up the hands so that the minute hand was short and the hour hand was long.
The first time the apprentice returned to the client was about 2 hours and 10 minutes after he had set the clock at six.The long had moved olny from twelve to a little past two. The little made two whole circles and an additional 10 minutes. Thus the clock showed the correct time.
The next day around 7:o5 a.m.he came a second time,13 hours and 15 minutes after he had set the clock for six. The long had, acting as the hour hand,covered 13 hours to reach 1. The short hand made 13 full circles and 5 minutes, reaching 7, So the clock showed the correct time again.
Show Answer
As the problem says the apprentice mixed up the hands so that the minute hand was short and the hour hand was long.
The first time the apprentice returned to the client was about 2 hours and 10 minutes after he had set the clock at six.The long had moved olny from twelve to a little past two. The little made two whole circles and an additional 10 minutes. Thus the clock showed the correct time.
The next day around 7:o5 a.m.he came a second time,13 hours and 15 minutes after he had set the clock for six. The long had, acting as the hour hand,covered 13 hours to reach 1. The short hand made 13 full circles and 5 minutes, reaching 7, So the clock showed the correct time again.
The first time the apprentice returned to the client was about 2 hours and 10 minutes after he had set the clock at six.The long had moved olny from twelve to a little past two. The little made two whole circles and an additional 10 minutes. Thus the clock showed the correct time.
The next day around 7:o5 a.m.he came a second time,13 hours and 15 minutes after he had set the clock for six. The long had, acting as the hour hand,covered 13 hours to reach 1. The short hand made 13 full circles and 5 minutes, reaching 7, So the clock showed the correct time again.
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