What is the proper length for a lady's skirt?

What is the proper length for a lady’s skirt?

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Noah survived one and it was great

I am in your eye. I am a school child. I am a word of five. What am I?

This royal young lady had several short men following her and helping her in the forest!

What did the robber get his wife for her birthday?

Solve A+B+B+B+80+90=100 with No negative numbers

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What is the proper length for a lady’s skirt?

Answer: A little above two feet.

Solution:

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A little above two feet.

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Noah survived one and it was great

Answer: flood

Solution:

I am in your eye. I am a school child. I am a word of five. What am I?

Answer: Pupil.

Solution:

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Pupil.

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This royal young lady had several short men following her and helping her in the forest!

Answer: Snow White

Solution:

What did the robber get his wife for her birthday?

Answer: A stole.

Solution:

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A stole.

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Solve A+B+B+B+80+90=100 with No negative numbers

Answer: A is log[1/(10^10)] and B is log[1/(10^20)]

Solution:

Mathematical logical Solution:

log [1/(10^10)] = -10 log(10) = -10 ->A

log [1/(10^20)] = -20 log(10) = -20 ->B

Now,

So, LHS: A + 3B + 80 + 90

=> -10 + 3(-20) + 80 + 90

=> 100 -> RHS

Hence proved! ( No negative numbers though)

Hence, A is log[1/(10^10)] and B is log[1/(10^20)]

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What is the proper length for a lady’s skirt?

Answer: A little above two feet.

Solution: Show Answer A little above two feet.

Show Answer

Share with

You may also like..

Noah survived one and it was great

Answer: flood

Solution:

I am in your eye. I am a school child. I am a word of five. What am I?

Answer: Pupil.

Solution: Show Answer Pupil.

Show Answer

This royal young lady had several short men following her and helping her in the forest!

Answer: Snow White

Solution:

What did the robber get his wife for her birthday?

Answer: A stole.

Solution: Show Answer A stole.

Show Answer

Solve A+B+B+B+80+90=100 with No negative numbers

Answer: A is log[1/(10^10)] and B is log[1/(10^20)]

Solution: Mathematical logical Solution: log [1/(10^10)] = -10 log(10) = -10 ->A log [1/(10^20)] = -20 log(10) = -20 ->B Now, So, LHS: A + 3B + 80 + 90 => -10 + 3(-20) + 80 + 90 => 100 -> RHS Hence proved! ( No negative numbers though) Hence, A is log[1/(10^10)] and B is log[1/(10^20)]

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Solution:

Show Answer

A little above two feet.

Solution:

Show Answer

Pupil.

Solution:

Show Answer

A stole.

Solution:

Mathematical logical Solution:

log [1/(10^10)] = -10 log(10) = -10 ->A

log [1/(10^20)] = -20 log(10) = -20 ->B

Now,

So, LHS: A + 3B + 80 + 90

=> -10 + 3(-20) + 80 + 90

=> 100 -> RHS

Hence proved! ( No negative numbers though)

Hence, A is log[1/(10^10)] and B is log[1/(10^20)]