All the electricity was out in town and none of the street lights or traffic signals had power. A dark limousine was cruising down the newly paved blacktop, with its headlights off. A young boy dressed totally in black (with no reflectors) stepped out to cross the street. The moon wasn’t out and the boy had no flashlight, yet the driver stopped to let the boy cross the street. How did the driver see the boy?
Answer: The driver saw the boy because it was during the daylight hours.
Solution:
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Two little holes in the side of a hill riddle answer
Answer: Nose 😛
Solution:
Riddle answer for: Two little holes in the side of a hill. Just as you come to the cherry-red mill. Who am I?
Show answer
Correct answer: Nose 😛
Knowledge increases by sharing 🙂
Riddle answer for: Two little holes in the side of a hill. Just as you come to the cherry-red mill. Who am I?
Show answer
Correct answer: Nose 😛
Knowledge increases by sharing 🙂
When the celebrated German mathematician Karl Friedrich Gauss (1777-1855) was nine he was asked to add all the integers from 1 through 100. He quickly added 1 to 100, 2 to 99, and so on for 50 pairs of numbers each adding to 101. Answer: 50 X 101=5,050. What is the sum of all the digits in integers from 1 through 1,000,000,000? (That’s all the digits in all the numbers, not all the numbers themselves.)
Answer: The numbers can be grouped by pairs: 999,999,999 and 0; 999,999,998 and 1' 999,999,997 and 2; and so on.... There are half a billion pairs, and the sum of the digits in each pair is 81. The digits in the unpaired number, 1,000,000,000, add to 1. Then: (500,000,000 X 81) + 1= 40,500,000,001.
Solution:
Show Answer
The numbers can be grouped by pairs:
999,999,999 and 0;
999,999,998 and 1′
999,999,997 and 2;
and so on….
There are half a billion pairs, and the sum of the digits in each pair is 81. The digits in the unpaired number, 1,000,000,000, add to 1. Then:
(500,000,000 X 81) + 1= 40,500,000,001.
Show Answer
The numbers can be grouped by pairs:
999,999,999 and 0;
999,999,998 and 1′
999,999,997 and 2;
and so on….
There are half a billion pairs, and the sum of the digits in each pair is 81. The digits in the unpaired number, 1,000,000,000, add to 1. Then:
(500,000,000 X 81) + 1= 40,500,000,001.
999,999,999 and 0;
999,999,998 and 1′
999,999,997 and 2;
and so on….
There are half a billion pairs, and the sum of the digits in each pair is 81. The digits in the unpaired number, 1,000,000,000, add to 1. Then:
(500,000,000 X 81) + 1= 40,500,000,001.
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