Large as a mountain, small as a pea, Endlessly swimming in a waterless sea. What am I?
Answer: Asteroids.
Solution:
Share with
Facebook Comment
You may also like..
In the early 1900’s in England, there was two towns: town A and town B, and there was a huge river in between them. The only way across to each town was by a long bridge with a guard post in the middle. It took 20 minutes to cross the bridge from one side to the other and 10 minutes each way from the guards tower. There were no hiding spots on the bridge so people couldn’t sneak past, and the guard comes out every 5 minutes or so to check to see if anyone is trying to cross. The guards tower was placed because of a law that stated that no one was aloud to leave their own town into the other because of political reasons and anyone who was caught by the guard would be fined and told to turn back. Many people have tried to cross but have always been caught, even very fast runners have only able to make it past the guards tower before being caught. But one night someone was able to make it across….How did they do it?
Answer: Did you get it? The answer is that they went up close to the guards tower, turned around and started walking back to the town they came from, the guard caught them and assumed that they came the other way and sent them back! Hope you enjoyed this, please subscribe and check back soon for more riddles!
Solution:
Show Answer
Did you get it? The answer is that they went up close to the guards tower, turned around and started walking back to the town they came from, the guard caught them and assumed that they came the other way and sent them back! Hope you enjoyed this, please subscribe and check back soon for more riddles!
Show Answer
Did you get it? The answer is that they went up close to the guards tower, turned around and started walking back to the town they came from, the guard caught them and assumed that they came the other way and sent them back! Hope you enjoyed this, please subscribe and check back soon for more riddles!
There are 100 light bulbs lined up in a row in a long room. Each bulb has its own switch and is currently switched off. The room has an entry door and an exit door. There are 100 people lined up outside the entry door. Each bulb is numbered consecutively from 1 to 100. So is each person. Person No. 1 enters the room, switches on every bulb, and exits. Person No. 2 enters and flips the switch on every second bulb (turning off bulbs 2, 4, 6, …). Person No. 3 enters and flips the switch on every third bulb (changing the state on bulbs 3, 6, 9, …). This continues until all 100 people have passed through the room. What is the final state of bulb No. 64? And how many of the light bulbs are illuminated after the 100th person has passed through the room?
Answer: First think who will operate each bulb, obviously person #2 will do all the even numbers, and say person #10 will operate all the bulbs that end in a zero. So who would operate for example bulb 48: Persons numbered: 1 & 48, 2 & 24, 3 & 16, 4 & 12, 6 & 8 ........ That is all the factors (numbers by which 48 is divisible) will be in pairs. This means that for every person who switches a bulb on there will be someone to switch it off. This willl result in the bulb being back at it's original state. So why aren't all the bulbs off? Think of bulb 36:- The factors are: 1 & 36, 2 & 13, 6 & 6 Well in this case whilst all the factors are in pairs the number 6 is paired with it's self. Clearly the sixth person will only flick the bulb once and so the pairs don't cancel. This is true of all the square numbers. There are 10 square numbers between 1 and 100 (1, 4, 9, 16, 25, 36, 49, 64, 81 & 100) hence 10 bulbs remain on.
Solution:
Show Answer
First think who will operate each bulb, obviously person #2 will do all the even numbers, and say person #10 will operate all the bulbs that end in a zero. So who would operate for example bulb 48: Persons numbered: 1 & 48, 2 & 24, 3 & 16, 4 & 12, 6 & 8 …….. That is all the factors (numbers by which 48 is divisible) will be in pairs. This means that for every person who switches a bulb on there will be someone to switch it off. This willl result in the bulb being back at it’s original state. So why aren’t all the bulbs off? Think of bulb 36:- The factors are: 1 & 36, 2 & 13, 6 & 6 Well in this case whilst all the factors are in pairs the number 6 is paired with it’s self. Clearly the sixth person will only flick the bulb once and so the pairs don’t cancel. This is true of all the square numbers. There are 10 square numbers between 1 and 100 (1, 4, 9, 16, 25, 36, 49, 64, 81 & 100) hence 10 bulbs remain on.
Show Answer
First think who will operate each bulb, obviously person #2 will do all the even numbers, and say person #10 will operate all the bulbs that end in a zero. So who would operate for example bulb 48: Persons numbered: 1 & 48, 2 & 24, 3 & 16, 4 & 12, 6 & 8 …….. That is all the factors (numbers by which 48 is divisible) will be in pairs. This means that for every person who switches a bulb on there will be someone to switch it off. This willl result in the bulb being back at it’s original state. So why aren’t all the bulbs off? Think of bulb 36:- The factors are: 1 & 36, 2 & 13, 6 & 6 Well in this case whilst all the factors are in pairs the number 6 is paired with it’s self. Clearly the sixth person will only flick the bulb once and so the pairs don’t cancel. This is true of all the square numbers. There are 10 square numbers between 1 and 100 (1, 4, 9, 16, 25, 36, 49, 64, 81 & 100) hence 10 bulbs remain on.
Animal Riddles 
Classic Riddles 
Current Affairs 
Difficult Riddles 
Dirty Riddles 
Easy Riddles 
Food Riddles 
Good Riddles 
Kids Riddles 
Math Riddles 
Riddles 
Short Riddles 
What am I ?