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A boy presses a side of a blue pencil to a side of a yellow pencil, holding both pencils vertically. One inch of the pressed side of the blue pencil, measuring from its lower end, is smeared with paint. The yellow pencil is held steady while the boy slides the blue pencil down 1 inch, continueing to press it against the yellow one. He returns the blue pencil to its former position, then again it slides down 1 inch. He continues until he has lowered the blue pencil 5 times and raised it 5 times- 10 moves in all. Supposed that during this time the paint neither dries nor diminishes in quantity. How many inches of each pencil will be sneared with paint after the tenth move?
Answer: At the start, 1inch of the yellow pencil gets smeared with wet paint. As the blue pencil is moved downward, a second inch of the blue pencils smears a second inch of the yellow pencil. Each pair of down and up movesof the blue pencil smears 1 more inch of each pencil. 5 pairs of moves will smear 5 inches. This together with the initial inch, makes 6 inches for each pencil.
Solution:
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At the start, 1inch of the yellow pencil gets smeared with wet paint. As the blue pencil is moved downward, a second inch of the blue pencils smears a second inch of the yellow pencil.
Each pair of down and up movesof the blue pencil smears 1 more inch of each pencil. 5 pairs of moves will smear 5 inches. This together with the initial inch, makes 6 inches for each pencil.
Show Answer
At the start, 1inch of the yellow pencil gets smeared with wet paint. As the blue pencil is moved downward, a second inch of the blue pencils smears a second inch of the yellow pencil.
Each pair of down and up movesof the blue pencil smears 1 more inch of each pencil. 5 pairs of moves will smear 5 inches. This together with the initial inch, makes 6 inches for each pencil.
Each pair of down and up movesof the blue pencil smears 1 more inch of each pencil. 5 pairs of moves will smear 5 inches. This together with the initial inch, makes 6 inches for each pencil.
A man goes to work at the same time each day and travels part of his journey facing forwards and the remainder facing backwards. When he returns at the end of his working day, he only faces forwards. How can this be?
Answer: He works in the engine room of a liner! To get to work, he walks along the decks from his cabin facing forwards, and down the ladders between decks facing backwards. However, when he finishes, he only needs to face forwards to climb the ladders again and walk along the deck back to his cabin.
Solution:
Show Answer
He works in the engine room of a liner! To get to work, he walks along the decks from his cabin facing forwards, and down the ladders between decks facing backwards. However, when he finishes, he only needs to face forwards to climb the ladders again and walk along the deck back to his cabin.
Show Answer
He works in the engine room of a liner! To get to work, he walks along the decks from his cabin facing forwards, and down the ladders between decks facing backwards. However, when he finishes, he only needs to face forwards to climb the ladders again and walk along the deck back to his cabin.
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